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In principle, the address space of the x86 series could have been extended in later processors by increasing the shift value, as long as applications obtained their segments from the operating system and did not make assumptions about the equivalence of different segment:offset pairs.[note 11] In practice the use of "huge" pointers and similar mechanisms was widespread and the flat 32-bit addressing made possible with the 32-bit offset registers in the 80386 eventually extended the limited addressing range in a more general way (see below). Intel could have decided to implement memory in 16 bit words (which would have eliminated the BHE signal along with much of the address bus complexities already described). This would mean that all instruction object codes and data would have to be accessed in 16-bit units. Users of the 8080 long ago realized, in hindsight, that the processor makes very efficient use of its memory. By having a large number of 8-bit object codes, the 8080 produces object code as compact as some of the most powerful minicomputers on the market at the time.[7]:5–26 If the 8086 is to retain 8-bit object codes and hence the efficient memory use of the 8080, then it cannot guarantee that (16-bit) opcodes and data will lie on an even-odd byte address boundary. The first 8-bit opcode will shift the next 8-bit instruction to an odd byte or a 16-bit instruction to an odd-even byte boundary. By implementing the BHE signal and the extra logic needed, the 8086 has allows instructions to exist as 1-byte, 3-byte or any other odd byte object codes.[7]:5–26 Simply put: this is a trade off. If memory addressing is simplified so that memory is only accessed in 16-bit units, memory will be used less efficiently. Intel decided to make the logic more complicated, but memory use more efficient. This was at a time when memory size was considerably smaller, and at a premium, than that which users are used to today.[7]:5–26In principle, the address space of the x86 series could have been extended in later processors by increasing the shift value, as long as applications obtained their segments from the operating system and did not make assumptions about the equivalence of different segment:offset pairs.[note 11] In practice the use of "huge" pointers and similar mechanisms was widespread and the flat 32-bit addressing made possible with the 32-bit offset registers in the 80386 eventually extended the limited addressing range in a more general way (see below). Intel could have decided to implement memory in 16 bit words (which would have eliminated the BHE signal along with much of the address bus complexities already described). This would mean that all instruction object codes and data would have to be accessed in 16-bit units. Users of the 8080 long ago realized, in hindsight, that the processor makes very efficient use of its memory. By having a large number of 8-bit object codes, the 8080 produces object code as compact as some of the most powerful minicomputers on the market at the time.[7]:5–26 If the 8086 is to retain 8-bit object codes and hence the efficient memory use of the 8080, then it cannot guarantee that (16-bit) opcodes and data will lie on an even-odd byte address boundary. The first 8-bit opcode will shift the next 8-bit instruction to an odd byte or a 16-bit instruction to an odd-even byte boundary. By implementing the BHE signal and the extra logic needed, the 8086 has allows instructions to exist as 1-byte, 3-byte or any other odd byte object codes.[7]:5–26 Simply put: this is a trade off. If memory addressing is simplified so that memory is only accessed in 16-bit units, memory will be used less efficiently. Intel decided to make the logic more complicated, but memory use more efficient. This was at a time when memory size was considerably smaller, and at a premium, than that which users are used to today.[7]:5–26In principle, the address space of the x86 series could have been extended in later processors by increasing the shift value, as long as applications obtained their segments from the operating system and did not make assumptions about the equivalence of different segment:offset pairs.[note 11] In practice the use of "huge" pointers and similar mechanisms was widespread and the flat 32-bit addressing made possible with the 32-bit offset registers in the 80386 eventually extended the limited addressing range in a more general way (see below). Intel could have decided to implement memory in 16 bit words (which would have eliminated the BHE signal along with much of the address bus complexities already described). This would mean that all instruction object codes and data would have to be accessed in 16-bit units. Users of the 8080 long ago realized, in hindsight, that the processor makes very efficient use of its memory. By having a large number of 8-bit object codes, the 8080 produces object code as compact as some of the most powerful minicomputers on the market at the time.[7]:5–26 If the 8086 is to retain 8-bit object codes and hence the efficient memory use of the 8080, then it cannot guarantee that (16-bit) opcodes and data will lie on an even-odd byte address boundary. The first 8-bit opcode will shift the next 8-bit instruction to an odd byte or a 16-bit instruction to an odd-even byte boundary. By implementing the BHE signal and the extra logic needed, the 8086 has allows instructions to exist as 1-byte, 3-byte or any other odd byte object codes.[7]:5–26 Simply put: this is a trade off. If memory addressing is simplified so that memory is only accessed in 16-bit units, memory will be used less efficiently. Intel decided to make the logic more complicated, but memory use more efficient. This was at a time when memory size was considerably smaller, and at a premium, than that which users are used to today.[7]:5–26In principle, the address space of the x86 series could have been extended in later processors by increasing the shift value, as long as applications obtained their segments from the operating system and did not make assumptions about the equivalence of different segment:offset pairs.[note 11] In practice the use of "huge" pointers and similar mechanisms was widespread and the flat 32-bit addressing made possible with the 32-bit offset registers in the 80386 eventually extended the limited addressing range in a more general way (see below). Intel could have decided to implement memory in 16 bit words (which would have eliminated the BHE signal along with much of the address bus complexities already described). This would mean that all instruction object codes and data would have to be accessed in 16-bit units. Users of the 8080 long ago realized, in hindsight, that the processor makes very efficient use of its memory. By having a large number of 8-bit object codes, the 8080 produces object code as compact as some of the most powerful minicomputers on the market at the time.[7]:5–26 If the 8086 is to retain 8-bit object codes and hence the efficient memory use of the 8080, then it cannot guarantee that (16-bit) opcodes and data will lie on an even-odd byte address boundary. The first 8-bit opcode will shift the next 8-bit instruction to an odd byte or a 16-bit instruction to an odd-even byte boundary. By implementing the BHE signal and the extra logic needed, the 8086 has allows instructions to exist as 1-byte, 3-byte or any other odd byte object codes.[7]:5–26 Simply put: this is a trade off. If memory addressing is simplified so that memory is only accessed in 16-bit units, memory will be used less efficiently. Intel decided to make the logic more complicated, but memory use more efficient. This was at a time when memory size was considerably smaller, and at a premium, than that which users are used to today.[7]:5–26In principle, the address space of the x86 series could have been extended in later processors by increasing the shift value, as long as applications obtained their segments from the operating system and did not make assumptions about the equivalence of different segment:offset pairs.[note 11] In practice the use of "huge" pointers and similar mechanisms was widespread and the flat 32-bit addressing made possible with the 32-bit offset registers in the 80386 eventually extended the limited addressing range in a more general way (see below). Intel could have decided to implement memory in 16 bit words (which would have eliminated the BHE signal along with much of the address bus complexities already described). This would mean that all instruction object codes and data would have to be accessed in 16-bit units. Users of the 8080 long ago realized, in hindsight, that the processor makes very efficient use of its memory. By having a large number of 8-bit object codes, the 8080 produces object code as compact as some of the most powerful minicomputers on the market at the time.[7]:5–26 If the 8086 is to retain 8-bit object codes and hence the efficient memory use of the 8080, then it cannot guarantee that (16-bit) opcodes and data will lie on an even-odd byte address boundary. The first 8-bit opcode will shift the next 8-bit instruction to an odd byte or a 16-bit instruction to an odd-even byte boundary. By implementing the BHE signal and the extra logic needed, the 8086 has allows instructions to exist as 1-byte, 3-byte or any other odd byte object codes.[7]:5–26 Simply put: this is a trade off. If memory addressing is simplified so that memory is only accessed in 16-bit units, memory will be used less efficiently. Intel decided to make the logic more complicated, but memory use more efficient. This was at a time when memory size was considerably smaller, and at a premium, than that which users are used to today.[7]:5–26In principle, the address space of the x86 series could have been extended in later processors by increasing the shift value, as long as applications obtained their segments from the operating system and did not make assumptions a

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23 Oct Mobile for sale ₹ 350
24 Oct Swift i10 ₹ 3500

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